power series solution of differential equations の結果 ~ Nyosspixwthm

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$√完了しました！ (1-x^2)y'' 2xy'=0 233394-(1-x^2)y''-xy'=0$

2 Using this in Equation 25 we obtain @'ny @x = 2 2x @x2( 1) 2x 2 4 2x yiv y00 (28) It is obvious what is going on The process is going ...